If sin x = 12/13, where 0° < x < 90°, find the value of 1 – cos\(^2\)x
- 25/169
- 64/169
- 105/169
-
144/169
- 8/13
The correct answer is: D
Explanation
\(\sin x = \frac{12}{13}\)
\(\cos x = \frac{5}{13}\)
\(\cos^{2} x = (\frac{5}{13})^2 = \frac{25}{169}\)
\(1 - \cos^{2} x = 1 - \frac{25}{169}\)
= \(\frac{144}{169}\)