What is the probability that the total sum of seven would appear in toss of a fair die?
- 5/36
-
1/6
- 7/36
- 5/6
- 1
The correct answer is: B
Explanation
No of possible outcome = 36
Required outcome (R) = {(1, 6), (6, 1), (2, 5), (5, 2), (3, 4), (4, 3)}
n(R) = \(\frac{6}{36}\)
= \(\frac{1}{6}\)