MyStudyPals.com MyStudyPals.com
  • Login
  • Feed

Resources

  • 📰
    Latest School News
  • 📚
    Scholarships
  • 🎓
    JAMB Syllabus
  • 📝
    Jamb Brochure

Information

  • 🔗
    Contact US
  • 🔗
    Privacy Policy
  • 🔗
    Terms and Conditions
  • 🔗
    About US

What is the equation of the line PQ?

  • 📑 Past Questions
  • ⌛ Take CBT exam
  • 📟 Referral
  • 🎫 Support
  • 📢 Earnings
Mathematics WAEC 1994

What is the equation of the line PQ?

  • y = x - 5
  • y = x + 3
  • y = x + 5 checkmark
  • y = 2x + 3
  • y = 2x - 3

The correct answer is: C

Explanation

The points P(-2, 3) and Q(2, 7) are on the line.

Gradient of the line = \(\frac{7 - 3}{2 - (-2)}\)

= \(\frac{4}{4}\)

= 1

y = x + b

To find the intercept, we have

7 = 2 + b or 3 = -2 + b.

Solving for b, we get b = 5.

\(\therefore\) The line is y = x + 5.

Previous Question Next Question

Leave A Comment

© 2025 MyStudyPals.com