Find the value(s) of x for which the expression is undefined: \(\frac{6x – 1}{x^2 + 4x – 5}\)
- +4 or+1
-
-5 or +1
- -5 or -1
- +5 or -1
- \(\frac{1}{6}\)
The correct answer is: B
Explanation
\(\frac{6x - 1}{x^2 + 4x - 5}\)
The expression is undefined when \(x^2 + 4x - 5 = 0\)
\(x^2 + 5x - x - 5 = 0\)
\(x(x + 5) - 1(x + 5) = 0\)
\((x - 1)(x + 5) = 0\)
The expression is undefined when x = 1 or -5.