
In the diagram above, ∠PRQ = 90°, ∠QPR = 30° and /PQ/ = 10 cm. Find y.
The correct answer is: B
Explanation
\(\sin 30° = \frac{y}{10}\)
\(y = 10 \sin 30° = 10 \times 0.5 = 5 cm\)
In the diagram above, ∠PRQ = 90°, ∠QPR = 30° and /PQ/ = 10 cm. Find y.
\(\sin 30° = \frac{y}{10}\)
\(y = 10 \sin 30° = 10 \times 0.5 = 5 cm\)