The bearing of two points Q and R from a point P are 030° and 120° respectively, lf /PQ/ = 12 m and /PR/ = 5 m, find the distance QR.
-
13m
- 11m
- 9m
- 7m
- 5m
The correct answer is: A
Explanation
x\(^2\) = 12\(^2\) + 5\(^2\)
x\(^2\) = 144 + 25
x\(^2\) = 169
x = \(\sqrt{169}\) = 13m.