Given that \(\frac{1}{2} \log_{10} P = 1\), find the value of P.
- 104
- 103
-
102
- 101
- 10-1
The correct answer is: C
Explanation
\(\frac{1}{2} \log_{10} P = 1\)
\(\log_{10} P^{\frac{1}{2}} = 1\)
\(P^{\frac{1}{2}} = 10^{1}\)
\(\implies P = 10^{2}\)