In the diagram PQ is a diameter of circle PMQN center O, if ∠PQM = 63o, find ∠MNQ
- 58.5o
- 44o
- 35o
- 31.5o
-
27o
The correct answer is: E
Explanation
In the given diagram,
< PMQ = 90º (< in a semi-circle)
<QPM = 180º - ( 90 + 63 )º = 27º
Therefore, <MNQ = <QPM = 27º ( <s in same segment)