Given that m = -3 and n = 2 find the value of \(\frac{3n^2 – 2m^3}{m}\)
-
-22
- -14
- 14
- 22
The correct answer is: A
Explanation
Given that m = -3, n = 2, the value of\(\frac{3n^2 - 2n^3}{m}\\
\frac{3(2)^2 -2(-3)^2}{-3}= \frac{12+54}{-3}=-22\)