If \(y = \sqrt{ax-b}\) express x in terms of y, a and b
The correct answer is: D
Explanation
\(y = \sqrt{ax-b}\)
\(y^2 = ax-b\)
\(y^2 +b = ax\)
\(x = \frac{y^2 + b}{a}\)
If \(y = \sqrt{ax-b}\) express x in terms of y, a and b
\(y = \sqrt{ax-b}\)
\(y^2 = ax-b\)
\(y^2 +b = ax\)
\(x = \frac{y^2 + b}{a}\)