If y varies inversely as x\(^2\), how does x vary with y?
- x varies inversely as y2
-
x varies inversely as √y
- x varies directly as y2
- x varies directly as y
The correct answer is: B
Explanation
\(y \propto \frac{1}{x^2}\)
\(y = \frac{k}{x^2}\)
\(x^2 = \frac{k}{y}\)
\(x = \frac{\sqrt{k}}{\sqrt{y}}\)
Since k is a constant, then \(\sqrt{k}\) is also a constant.
\(\therefore x \propto \frac{1}{\sqrt{y}}\)