A pole of length L leans against a vertical wall so that it makes an angle of 60o with the horizontal ground. If the top of the pole is 8m above the ground, calculate L.
- \(16\sqrt{3}m\)
- \(4\sqrt{3}m\)
- \(\frac{\sqrt{3}}{16}\)
-
\(\frac{16\sqrt{3}}{3}\)
The correct answer is: D
Explanation
When we rationalize gives \(\frac{16\sqrt{3}}{3}\)