In the diagram, DE||BC, |AD| = x cm and |DB| = |AE| = ycm. Find |CE| in terms of x and y
- x
- \(\frac{x^2}{y}\)
- \(\frac{y}{x^2}\)
-
\(\frac{y^2}{x}\)
The correct answer is: D
Explanation
\(\frac{x}{x+y}=\frac{y}{x+CE}\\xy + xCE = xy + y^2\\
∴xCE = y^2\\
CE=\frac{y^2}{x}\)