In the diagram, AB is a vertical pole and BC is horizontal. If |AC| = 10m and |BC| = 5m, calculate the angle of depression of C from A
- 63o
-
60o
- 45o
- 27o
The correct answer is: B
Explanation
In triangle ABC, \(\frac{BC}{AC} = \cos \theta\)
\(\implies \cos \theta = \frac{5}{10} = 0.5\)
\(\theta = \cos^{-1} (0.5) = 60°\)