Evaluate \((20_{three})^2 – (11_{three})^2\) in base three
- 101
- 121
-
202
- 2020
The correct answer is: C
Explanation
\((20_{three})^2 - (11_{three})^2\)
= \((20_{3} - 11_{3})(20_{3} + 11_{3})\)
= \((2_{3})(101_{3})\)
= \(202_{3}\)