The nth term of a sequence is \(2^{2n-1}\). Which term of the sequence is \(2^9?\)
- 3rd
- 4th
-
5th
- 6th
The correct answer is: C
Explanation
\(T_{n} = 2^{2n - 1}\)
\(2^{2n - 1} = 2^9\)
\(2n - 1 = 9 \implies 2n = 9 + 1\)
\(2n = 10 \implies n = 5\)
The 5th term = 2\(^9\)