Given that sin \(P = \frac{5}{13}\), where p is acute, find the value of cos p – tan p
-
\(\frac{79}{156}\)
- \(\frac{85}{156}\)
- \(\frac{7}{13}\)
- \(\frac{8}{1}\)
The correct answer is: A
Explanation
\(BC^2 = 13^2 - 5^2\\
=169-25\\
BC = \sqrt{144} = 12\\
∴ cos P - tan P = \frac{12}{13} - \frac{5}{12}\\
=\frac{79}{156}\)