PQRS is a rhombus of side 16cm. The diagonal |QS| = 20cm. Calculate, correct to the nearest degree, ∠PQR
- 51o
- 64o
- 77o
-
103o
The correct answer is: D
Explanation
cos\(\alpha\) = \(\frac{10}{16}\) = 0.625\(\alpha\) = cos-1(0.625)
= 51.3o
∠PQR = 2\(\alpha\)
= 2(51.3o)
= 102.6
= 103o