If log 2 = 0.3010 and log 2\(^y\) = 1.8062, find; correct to the nearest whole number, the value of y.
-
6
- 5
- 4
- -5
The correct answer is: A
Explanation
\(log2 = 0.3010\hspace{1mm}given\\
log2^y = 1.8062\\
∴ ylog2 = 1.8062\\
y=\frac{1.8062}{logy}=\frac{1.8062}{0.3010}=6\)