Find the nth term of the sequence 4, 10, 16 ,…
-
2(3n- 1)
- 2(2 + 3 n-1)
- 2 n + 2
- 2(3n+2)
The correct answer is: A
Explanation
\(T_{1} = 4; T_2 = 10; T_3 = 16\)
\(T_{2} - T_1 = T_3 - T_1 = 6\)
\(T_n = a + (n - 1) d\)
= \(4 + (n - 1) \times 6\)
= \(4 + 6n - 6\)
= \(6n - 2\)
= 2(3n - 1)