Simplify \(\frac{1}{1-x} + \frac{2}{1+x}\)
- \(\frac{x+3}{1-x^2}\)
- \(\frac{x-3}{1+x^2}\)
-
\(\frac{3-x}{1-x^2}\)
- \(\frac{3-x}{1+x^2}\)
The correct answer is: C
Explanation
\(\frac{1}{1-x} + \frac{2}{1+x}\\\frac{1+x+2-2x}{(1-x)(1+x)} = \(\frac{3-x}{1-x^2}\)\)