The lengths of the parallel sides of a trapezium are 9 cm and 12 cm. lf the area of the trapezium is 105 cm2, find the perpendicular distance between the parallel sides.
- 5cm
- 7cm
-
10cm
- 15cm
The correct answer is: C
Explanation
\(\frac{1}{2}(a+b)\times h = 105cm^2\\\frac{1}{2}(9+12)\times h = 105\\
h = \frac{105 \times 2}{21} = 10cm\)