In the diagram O is the center of the circle, ∠SOR = 64° and ∠PSO = 36°….

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Mathematics WAEC 2002

In the diagram O is the center of the circle, ∠SOR = 64° and ∠PSO = 36°. Calculate ∠PQR

  • 100o
  • 96o
  • 94o
  • 86o checkmark

The correct answer is: D

Explanation

< OSR = < ORS = \(\frac{180° - 64°}{2}\) = 58°

< PSR = 36° + 58° = 94°

< PSR + < PQR = 180°

94° + < PQR = 180° \(\implies\) < PQR = 180° - 94° = 86°

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