Find the value of x in the equation 3x\(^2\) – 8x – 3 = 0
- \(\frac{1}{3},-3\)
- \(-\frac{1}{3},-3\)
-
\(-\frac{1}{3},3\)
- \(\frac{1}{3},3\)
The correct answer is: C
Explanation
3x\(^2\) - 8x - 3 = 0
3x\(^2\) - 9x + x - 3 = 0
3x(x - 3) + 1(x - 3) = 0
(3x + 1)(x - 3) = 0
3x = -1 \(\implies\) x = \(-\frac{1}{3}\)
or x = 3.