Out of 60 members of an Association, 15 are Doctors and 9 are Lawyers. If a member is selected at random from the Association, what is the probability that the member is neither a Doctor Nor a Lawyer
-
\(\frac{3}{5}\)
- \(\frac{9}{10}\)
- \(\frac{3}{20}\)
- \(\frac{1}{4}\)
The correct answer is: A
Explanation
Member that are neither doctors nor lawyers = 60-(15+9)=36Probability (Not doctors ad not lawyers) \(=\frac{36}{60}\\
=\frac{6}{10}=\frac{3}{5}\)