Find the values of x for which \( \frac{1}{2x^2 – 13x +15} \) is not defined,
-
5 or \( \frac{3}{2} \)
- 1 or \( \frac{15}{13} \)
- 2 or 15
- 13 or 15
The correct answer is: A
Explanation
The fraction is undefined when the denominator is equal to zero\(2x^2 - 13x + 15 = 0\\
2x^2 - 3x - 10x + 15\\
x(2x-3)-5(2x-3) = 0\\
(2x-3)(x-5)=0\\
x = \frac{3}{2} or x = 5\)