If \(\frac{3^{(1-n)}}{9^{-2n}}=\frac{1}{9}\) find n
- \(-\frac{3}{2}\)
- \(\frac{1}{3}\)
-
-1
- -3
The correct answer is: C
Explanation
\(\frac{3^{(1-n)}}{9^{-2n}}=\frac{1}{9}\\3^{1-n}\times 3^{-2(-2n)} = 3^{-2}\\
1-n-2(-2n)= -2\\
1-n+4n=-2\\
n=-1\)