A right circular cone is such that its radius r is twice its height h. Find its volume in terms of h
- \(\frac{2}{3}\pi h^2\)
- \(\frac{1}{12}\pi h^3\)
- \(\frac{4}{3}\pi h^2\)
-
\(\frac{4}{3}\pi h^3\)
The correct answer is: D
Explanation
Volume of a cone = \(\frac{\pi r^2 h}{3}\)
r = 2h.
V = \(\frac{\pi \times (2h)^2 \times h}{3}\)
= \(\frac{4}{3} \pi h^3\)