If \(\left(\frac{1}{4}\right)^{(2-y)} = 1\), find y.
- -2
- \(-\frac{1}{2}\).
- \(\frac{1}{2}\)
-
2
The correct answer is: D
Explanation
\(2^{-2(2-y)}-x=2^{0}; -4 + 2y = 0\\
2y = 4; y = 2\)