If \(\left(\frac{1}{4}\right)^{(2-y)} = 1\), find y.
The correct answer is: D
Explanation
\(2^{-2(2-y)}-x=2^{0}; -4 + 2y = 0\\
2y = 4; y = 2\)
If \(\left(\frac{1}{4}\right)^{(2-y)} = 1\), find y.
\(2^{-2(2-y)}-x=2^{0}; -4 + 2y = 0\\
2y = 4; y = 2\)