In the diagram, PQRW is a circle. Line P, V and QR are produced to meet at M, where ∠WMR = 30o and |WM| = |MR| Find the value of x
- 10o
-
25o
- 35o
- 60o
The correct answer is: B
Explanation
MPQ = PQM = 3x; ∆MPQMPQ + PQM + PMQ = 180o; 3x + 3x + 30o = 180o
6x \times 30o = 180o; 6x + 180o - 30o; 6x + 150o
\(x = \frac{150}{6} = 25^{\circ}\)