Find the range of values of x for which\(\frac{x+2}{4}-\frac{x+1}{3}>\frac{1}{2}\)
- x > 4
- x > -4
- x < 4
-
x < -4
The correct answer is: D
Explanation
\(\frac{x+2}{4}-\frac{x+1}{3}>\frac{1}{2}\\\frac{3(x+2)-4(x+1)>6}{12}; 3x + 6 – 4x – 4 > 6\
-x +2>6; -x > 4; x < -4\)