A fair die is tossed once, what is the probability of obtaining neither 5 or 2
- \(\frac{5}{6}\)
-
\(\frac{2}{3}\)
- \(\frac{1}{2}\)
- \(\frac{1}{6}\)
The correct answer is: B
Explanation
Probability of obtaining a 5 is P(5)=\(\frac{1}{6}\)Probability of obtaining a 2 is P(2)=\(\frac{1}{6}\)
Probability of obatining either 2 or 5 = P(2∪5) = \(\frac{2}{6}\)
Probability of obtaining neither 5 or 2 = \(1 - \frac{2}{6}=\frac{4}{6}=\frac{2}{3}\)