Solve the equation \(\frac{2y-1}{3} – \frac{3y-1}{4} = 1\)
- -8
-
-13
- 13
- 19
The correct answer is: B
Explanation
\(\frac{4(2y-1)-3(3y-1)}{12}=12 \Rightarrow 8y - 4 - 9y + 3 = 12 \\
\Rightarrow -y-1=12\Rightarrow -y=13\Rightarrow y=-13\)