Given that the root of an the equation \(2x^2 + (k+2)x+k=0\) is 2, find the value of k
-
-4
- -2
- -1
- \(-\frac{1}{4}\)
The correct answer is: A
Explanation
Substituting for x in the equation\(2(2)^2 + (k+2)2+k = 0 \Rightarrow 8 +2k + 4 + k =0 \Rightarrow 3k =-12; k=-4\)