Given that the root of an the equation \(2x^2 + (k+2)x+k=0\) is 2, find the…

Mathematics WAEC 2005

Given that the root of an the equation \(2x^2 + (k+2)x+k=0\) is 2, find the value of k

  • -4 checkmark
  • -2
  • -1
  • \(-\frac{1}{4}\)

The correct answer is: A

Explanation

Substituting for x in the equation
\(2(2)^2 + (k+2)2+k = 0 \Rightarrow 8 +2k + 4 + k =0 \Rightarrow 3k =-12; k=-4\)
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