Simplify: \(\frac{2}{3xy} – \frac{3}{4yz}\)
- \(\frac{2-x}{12xyz}\)
- \(\frac{2z-3x}{12xyz}\)
- \(\frac{4z-3x}{12xyz}\)
-
\(\frac{8z-9x}{12xyz}\)
The correct answer is: D
Explanation
\(\frac{2}{3xy} - \frac{3}{4yz} = \frac{2(4)-3(3x)}{12xyz} = \frac{8z-9x}{12xyz}\)