The angle of elevation of the top of a cliff 15 meters high from a landmark is 60º. How far is the landmark from the foot of the cliff? Leave your answer in surd form
- \(15\sqrt{3}m\)
- \(15\sqrt{2}m\)
- \(10\sqrt{3}m\)
-
\(5\sqrt{3}m\)
The correct answer is: D
Explanation
Tan 60º = \(\frac{15}{x}\)
cross multiply:
x = \(\frac{15}{\sqrt3}\) = 5\(\sqrt3\)m