\(\begin{array}{c|c} x & 1 & 4 & p \\ \hline y & 0.5 & 1 & 2.5\end{array}\). The table above satisfies the relation y = k\(\sqrt{x}\), where k is a positive constant. Find the value of K.
-
0.5
- 1
- 1.5
- 2
The correct answer is: A
Explanation
y = k\(\sqrt{x}\) when y = 1, x = 4k = \(\frac{y}{\sqrt{x}}\)
= \(\frac{1}{\sqrt{4}}\)
= \(\frac{1}{2}\)
= 0.5