\(\begin{array}{c|c} x & 1 & 4 & p \\ \hline y & 0.5 & 1 & 2.5\end{array}\). The table below satisfies the relation y = k\(\sqrt{x}\), where k is a positive constant. Find the value of P,
- 2
- 4
- 10
-
25
The correct answer is: D
Explanation
From y = \(\frac{1}{2} \sqrt{x}\)
when y = 2.5 or \(\frac{5}{2}\), x = P
\(\frac{5}{2} \times \frac{1}{2} \sqrt{P}\)
\(\sqrt{P} = \frac{10}{2} = 5\)
P = \(5^2\)
= 25