What is the place value of 9 in the number 3.0492?
- \(\frac{9}{10000}\)
-
\(\frac{9}{1000}\)
- \(\frac{9}{100}\)
- \(\frac{9}{10}\)
The correct answer is: B
Explanation
Place value of 9 in 3.0492= 0.009
= \(\frac{9}{1000}\)