If p = [\(\frac{Q(R – T)}{15}\)]\(^ \frac{1}{3}\), make T the subject of the relation
- T = R + \(\frac{P^3}{15Q}\)
-
T = R - \(\frac{15P^3}{Q}\)
- T = R + \(\frac{P^3}{15Q}\)
- T = 15R - \(\frac{Q}{P^3}\)
The correct answer is: B
Explanation
Cubic both sides; P3 = \(\frac{Q(R - T)}{15}\)(cross multiplication) Q(R - T) = 15P3
(divide both sides by Q); R - T = 15\(\frac{1}{Q}\)
(subtract r from both sides) - T = \(\frac{15P^3}{Q - R}\)
T = R - \(\frac{15P^3}{Q}\)