A sector of a circle of radius 14cm containing an angle 60o is folded to form a cone. Calculate the radius of the base of the cone.
- \(5\frac{1}{2}cm\)
- \(4\frac{2}{3}cm\)
- \(3\frac{1}{2}cm\)
-
\(2\frac{1}{3}cm\)
The correct answer is: D
Explanation
\(r=\frac{\theta \times l}{360^{\circ }}\\r=?, \theta =60^{\circ }\), l = radius of the orginal sector of a circle = 14cm
\(r=\frac{60\times 14}{360}=\frac{7}{3}=2\frac{1}{3}cm\)