Find the value of a if log\(_{10}\) a + log\(_{10}\)a\(^2\) = 0.9030
The correct answer is: B
Explanation
log\(_{10}\) a + log\(_{10}\)a\(^2\) = 0.9030
log (a x a\(^2\)) = 0.9030
log a\(^3\) = 0.9030
a\(^3\) = 10^.9030(antilogarithm table)
a\(^3\) = 7.998
a = 3\(\sqrt{7.998}\)
a = 1.9998 โ 2.0