make w the subject of the relation \(\frac{a + bc}{wd + f}\) = g
The correct answer is: A
Explanation
\(\frac{a + bc}{wd + f}\) = g(cross multiply)a = bc + wdg + fg
wdg = a + bc - fg
w = \(\frac{a + bc - fg}{dg}\)
make w the subject of the relation \(\frac{a + bc}{wd + f}\) = g