Given that x = 2 and y = -\(\frac{1}{4}\), evaluate \(\frac{x^2y – 2xy}{5}\)
-
zero
- \(\frac{1}{5}\)
- 1
- 2
The correct answer is: A
Explanation
Given; x = 2; y = \(\frac{-1}{4}\)= \(\frac{x^2y - 2xy}{5}\)
= \(\frac{2^2(\frac{-1}{4}) - 2(2)(\frac{-1}{4})}{5}\)
= \(\frac{4(\frac{-1}{4}) + 4(\frac{-1}{4})}{5}\)
= \(\frac{1 + 1}{5}\)
= \(\frac{0}{5}\)
= 0