If 4y is 9 greater than the sum of y and 3x, by how much is y greater than x?
The correct answer is: A
Explanation
4y - 9 > y + 3x; 4y - y > 3x + 9
3y > 3(x + 3); y = > \(\frac{3(x + 3)}{3}\)
y > x + 3; y - 3 > x
y is greater than x by 3
If 4y is 9 greater than the sum of y and 3x, by how much is y greater than x?
4y - 9 > y + 3x; 4y - y > 3x + 9
3y > 3(x + 3); y = > \(\frac{3(x + 3)}{3}\)
y > x + 3; y - 3 > x
y is greater than x by 3