The angles of a quadrilateral are (x + 10)o, 2yo, 90o and (100 - y)o,...

The angles of a quadrilateral are (x + 10)^o, 2y^o, 90^o and (100 – y)^o, Find y in terms of x

The correct answer is: C

Sum of the angles in a quadrilateral = 360^o

(x + 10^o) + 2y + 90^o + 100 - y = 360^o

x + y + 200 = 360^o

y = 360 - 200 - x

y = 160 - x