If log 2 = x, log 3 = y and log 7 = z, find, in terms of x, y and z, the value of log (\(\frac{28}{3}\))
- 2x + y - z
-
2x + z - y
- x + y - 2x
- x + x - y
The correct answer is: B
Explanation
log (\(\frac{28}{3}) = \log (\frac{7 \times 4}{3})\)
= log 7 + log 4 - log 3
log 7 + log \(2^2\) - log 3 = log 7 + 2log2 - log 3
= z + 2x - y
= 2x + z - y