Each of the interior angles of a regular polygon is 140o. Calculate the sum of all the interior angles of the polygon
- 1080o
-
1260o
- 1800o
- 2160o
The correct answer is: B
Explanation
Each interior angle = 140\(\frac{(n - 2) \times 180}{n} = 140\)
(n - 2) x 180 = 140n
150 - 360 = 140n
180m - 140n = 360
40n - 360
n = \(\frac{360}{40}\)
n = 9
Sum of all interior angles = (n - 2) x 180
= (9 - 2) x 180
= 7 x 180
= 1260