In the diagram, IG is parallel to JE, JEF = 120o and FHG = 130o,...

In the diagram, IG is parallel to JE, JEF = 120^o and FHG = 130^o, fins the angle marked t

The correct answer is: B

Now, t + 60^o + 50^o = 180^o

t = 180^o - 110^o

t = 70^o