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Solve the inequality: 3(x + 1) \(\leq\) 5(x + 2) + 15

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Mathematics WAEC 2010

Solve the inequality: 3(x + 1) \(\leq\) 5(x + 2) + 15

  • x \(\geq\) -14
  • x \(\leq\) - 14
  • x \(\geq\) -11 checkmark
  • x \(\leq\) - 11

The correct answer is: C

Explanation

3(x + 1) \(\leq\) 5(x + 2) + 15

3x + 3 \(\leq\) 5x + 10 + 15

3x - 5x \(\leq\) 10 + 15 - 3

-2x \(\leq\) 22

x \(\geq\) \(\frac{-22}{2}\)

x \(\geq\) -11

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